Problema Geometrie
3:17 AM | Author: Florin Todea
Un trapez isoscel care are diagonalele perpendiculare si linia mijlocie este de 24 cm. Sa se afle aria trapezului.

REZOLVARE

A= (B+b)*h/2 =24*h= 24*EF

MN= l.m(linia mijlocie)= B+b/2=24

∆FOC dreptunghic isoscel=>OF≡FC≡DC/2

∆AOE dreptunghic isoscel=>OE≡AE≡AB/2

EF=h=OF+OE=DC/2+AB/2==(AB+DC)/2=l.m.=24

A=24*24=576 cm^2

Aria=576cm`2

Deci in concluzie nu este un caz particular!
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10 comments:

On December 6, 2007 at 12:21 AM , Sergiu said...

desenui copiat duoa tibi :))))

 
On December 6, 2007 at 12:28 AM , maria said...

frumos desen...

 
On December 6, 2007 at 12:28 AM , Anonymous said...

imi place cum ai rezolvat... si am facut si eu lafel ;) thx

 
On December 6, 2007 at 12:28 AM , cosmin said...

copiat

 
On December 6, 2007 at 12:31 AM , jurgiu said...

am crezut ca teai lasat de copiat

 
On December 6, 2007 at 12:40 AM , Vlad said...

desenul copiat..rezolvarea e ok:)

 
On December 6, 2007 at 12:42 AM , aurelian said...

nu ai copiat ii bine

 
On December 6, 2007 at 12:44 AM , ciprian said...

cippri:ii cea mai buna rezolvare,si desenul ii facut singur,nu lipseste nimic.

 
On December 6, 2007 at 12:50 AM , Alex said...

desen copiat de la tibi !!!! rezolvarea unica :<

 
On December 6, 2007 at 8:34 AM , Dacian said...

copiat...adika vezi k nu ai copiat bn...

 
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